A is 6 times as fast as B and takes 100 days less to complete a work than B find

A=20 days & B=120 days.. and together they will do the work in 17.14 days
11 years agoHelpfull: Yes(11) No(6)
ratio of time taken by A n B is
a:b=1:6
b takes x days
then a takes x-100
so x-100/x=1/6
x=120
b takes 120 days n a takes 20 days
total 140
11 years agoHelpfull: Yes(9) No(17)
17 1/7 or 17.14 days
If A & B are the days taken to complete the work by A & B respectively
Given B-A=100 as A=B/6, so B-(B/6)=100 or B=120, A=20
Days to complete the work by A & B together=1/[(1/20)+(1/120)]=120/7=17 1/7
11 years agoHelpfull: Yes(7) No(3)
A is 6 times faster than B.So,the time taken by B is B=6A
Given that A completes the work 100 days before B,then
B-A=100=>6A-A=100=>5A=100 and A=20,B=120
So,the total number of days taken by both is 140 days
11 years agoHelpfull: Yes(3) No(4)
A:B= 1:6
A-B= 100 Solving these eqns. u will get A=20 & B=120 total no.of days =140
11 years agoHelpfull: Yes(0) No(10)
let total number of days taken by A be x,then B's total work will be done in 6x
then 6x-x=100--> x=20
therfore ans is 120 n 20
11 years agoHelpfull: Yes(0) No(2)
Given n=6 and D=100,apply this rule D*n/n^2-1..
answer is 120/7
11 years agoHelpfull: Yes(0) No(1)

A is 6 times as fast as B and takes 100 days less to complete a work than B. find the total no of days taken by A and B to complete the work.