The value of diamond varies directly as the square of its weight.if a diamond falls and breaks into two pieces with weights in the ratio 2:3what is the loss percentage in the value

• answer is 48%.
  here let the c.p of 1w iz Re. 1
  then c.p for 5w =5^2=25
  c.p. for 2w =2^2=4
  c.p for 3w =3^2=9
  loss %= (25-13)/25*100=12*4=48.
• 10 years agoHelpfull: Yes(22) No(0)
• the cost of diamond in the original state is proportional to x^2
  when it is fallen it breaks into two peices 2y and the 3y
  5y=x
  the weight with respect to original is 2x/5 and 3x/5
  so the total cost 13x^2 / 25
  so percentage cost will be 13/25*100= 52%
  so the percentage loss will be 48%
• 10 years agoHelpfull: Yes(15) No(2)
• the cost of diamond in the original state is (2x+3x)^2 = 25x^2
  After falling
  the cost of diamond= (2x)^2+(3x)^2
  = 13x^2
  so loss=25x^2-13x^2=12x^2
  so loss percentage will be (12x^2/25x^2)*100= 48%
• 10 years agoHelpfull: Yes(2) No(0)
• loss is of 48%
• 10 years agoHelpfull: Yes(1) No(0)
• loss 48%
  as new value is 13/25 times the original value
• 10 years agoHelpfull: Yes(1) No(0)
• Since it is broken in two part by weight its two ratio 2:3
  That mean oroginal weight =2+3=5
  Given that cost of it is equal to square of its weight.
  so cost of original=5^2=25
  nd cost of broken parts are......2^2 nd 3^2 that is 4 nd 9 ,
  so total cost is 9+4=13
  lose in cost=25-13=12
  Loss %=12/25)×100=48%
  
• 7 years agoHelpfull: Yes(0) No(0)