what are the last 2 digits of (2957)^3661??

• 57^1=57(last two digits)
  57^2=49(last two digits)
  57^3=93(last two digits)
  57^4=01(last two digits)
  
  57^5=57(last two digits)...here the repetation starts...so we go 4 different cases for different last 2 digits.. divide the power(3661) by 4 and take the remainder .. so, 3661%4=1..we the ans will be same as what is written in 1st case,i.e.,57^1=57... it says the final answer is 57
• 11 years agoHelpfull: Yes(28) No(0)
• ans is 57
  take the last two digits from 2957 i.e 57
  now count its cycle 57, 49, 93, 01, 57
  thus it comes as 4
  now divide 3661 by 4 , we get remainder 1 which means 57
  thus it is the required answer
  
• 11 years agoHelpfull: Yes(8) No(0)