A owes B Rs. 50. He agrees to pay B over a number of consecutive days starting on a Monday paying a single note of Rs. 10 or Rs. 20 on each day. In how many different ways can A repay B. (Two ways are said to be different , if and at least one day, a note of different denomination is given)

• Ans is 8 ways
  
• 10 years agoHelpfull: Yes(29) No(5)
• ans is 7 ways..
  10,10,10,20 = 4!/3! = 4 and
  20,20,10=3!/2!= 3 .. thus it becomes a total of 7 ways
• 10 years agoHelpfull: Yes(9) No(11)
• answer is 7
  (10,10,10,20) can be given in 4!/3!=4
  (10,20,20) can be given in 3!/2!=3
  total=4+3=7
• 10 years agoHelpfull: Yes(6) No(10)
• 10,10,10,10,10=1 way
  10,20,20=3!/2!=3 ways
  20,10,10,10=4!/3!=4 ways
  total=1+3+4=8 ways
  
• 9 years agoHelpfull: Yes(4) No(2)
• 10 10 10 10 10 -> 1 way
  10 20 20-> 3!/2! = 3 ways
  10 10 10 20 -> 4!/3!= 4 ways
  so total = 8 ways
• 9 years agoHelpfull: Yes(1) No(0)
• atleast one day notes of diff denomination is given..so possible ways(10,10,10,20)&(20,20,10)...for(10,10,10,20)=4!/3!=4..and for(20,20,10)=3!/2!=3..adding both we get 7
  
• 8 years agoHelpfull: Yes(0) No(0)
• 8 ways....
• 8 years agoHelpfull: Yes(0) No(0)