TCS
Company
Numerical Ability
Percentage
If M is 30% of Q, Q is 20% of P and N is 50% of P, then M/N is,
option
a) 3/250
b) 6/5
c) 4/2
d) 3/25
Read Solution (Total 13)
-
- 3/25
M/N=(30/100)(20/100)P/(50/100)P
which gives 3/25 - 11 years agoHelpfull: Yes(13) No(0)
- ans=3/25
M/N=(30*20/5000)=3/25 - 11 years agoHelpfull: Yes(4) No(1)
- 3/25 is correct one
- 11 years agoHelpfull: Yes(2) No(0)
- ans=3/5
n=50p/100 and q=20p/100 and m=30q/100 m/n=3*p*2/10*5*p - 11 years agoHelpfull: Yes(1) No(4)
- m=(30/100)q
q=(20/100)p
n=(50/100)p from this p=(100/50)n
m=(30/100)*(20/100)*(100/50)n
m/n=6/5 - 11 years agoHelpfull: Yes(1) No(4)
- ans will 3/25.if we assume p=x den N=50x/100=x/2 Q=20x/100=x/5
M=(30/100)*x/5=3x/50 nw M/N=(3x/50)/(x/2)=(3x/50)*(2/x)=3/25 - 11 years agoHelpfull: Yes(0) No(0)
- 3/25
let p=x then N=1/2X
Q=1/5X
M=3/50X&M/N=3/25 - 11 years agoHelpfull: Yes(0) No(0)
- which one is correct
- 11 years agoHelpfull: Yes(0) No(0)
- since M=.3Q, Q=.2P, N=.5P so M/N= (.3Q/.5P) here put Q=.2P
so M/N = (.06P/.5P) = .12 or 6/50 or 3/25 - 11 years agoHelpfull: Yes(0) No(0)
- Given that m=(30/100)*q
q=(20/100)*p
n=(50/100)*P => n=(1/2)*p => p=2n
subs p in 2nd eqn => q=(20/100)*2n
again subs q in 1st eqn => m=(30/100)*(20/100)*2n
=>m=3/25 n
so d ans is 3/25 - 11 years agoHelpfull: Yes(0) No(0)
- m=30/100*q/1
q=20/100*p/1
n=50/100*p/1
m/n=30/100*q*100/50*1/p
substitute q value in the equation
so,m/n=30/100*20/100*p/1*100/50*1/p
ans=3/25 - 11 years agoHelpfull: Yes(0) No(0)
- ans is 3/25
- 7 years agoHelpfull: Yes(0) No(0)
- 3/25
N = P/2
M = 3P/50 - 5 years agoHelpfull: Yes(0) No(0)
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