The citizens of planet nigiet are 6 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 (in base 8) buildings numbered 1 to 1000. How many 3s are used in numbering these buildings?
192
54
64
256

• Consider 3 in one's place. The possible numbers are
  3,13,23....,73
  103,113...,173....
  703,713...773
  i.e 8*8=64 times.
  Similarly consider 10's place
  30,31,31...37
  130,131,...137....
  730,731...737
  Again 8*8=64
  Now to hundred's place
  300,301...307....
  370,371,...377
  Again 8*8=64
  so total 64+64+64=192
  
  so a????
  
• 13 years agoHelpfull: Yes(24) No(3)
• for this type of questions answer will be always 3n^2
  so 3(8)^2=192
• 12 years agoHelpfull: Yes(9) No(3)
• ans:192
  3*8*8
• 13 years agoHelpfull: Yes(6) No(3)
• convert 1000 into base 8 form
  i.e 512
  No of 3s=512/8=64
• 13 years agoHelpfull: Yes(1) No(34)
• first calculate no.of 3 in 1 to 1000(on base 10)...
  i.e. 300
  now convert 300 into base 8... 8*2+0+0=64 answer
• 13 years agoHelpfull: Yes(0) No(30)