For which of the following n is the number 274 + 22058 + 22n
option
(a) 2012
(b) 2100
(c) 2011
(d) 2020

a perfect square?

• 2^74+2^2058+ 2^2n which is (a+b)^2 form
  (a+b)^2=a^2+b^2+2ab= (2^37)^2 + (2^n)^2 + 2^2058
  hence a=2^37
  b=2^n
  2ab = 2 * 2^37 * 2^n
  => 2^(38+n) = 2^2058
  =>38+n=2058
  =>n=2020
  
  
• 11 years agoHelpfull: Yes(35) No(0)
• 2020
• 11 years agoHelpfull: Yes(0) No(0)