In a clock the long hand is of 8cm and the short hand is of 7cm. if the clock runs for 4 days find out the total distance covered by both the hands.

• @arpit bro..there is a little mistake in ur expalanation.
  ans=1648*pi..
  explaination-
  
  4(2*2*pi*7+24*2*pi*8)=1648*pi
• 11 years agoHelpfull: Yes(46) No(5)
• 4 days = 96 hours
  long hand makes 1 round (i.e 2*pi*r) in 1 hour, so 96 rounds in 96 hours
  short hand makes 1 round in 12 hours, so 8 rounds in 96 hours
  Hence total distance = (96*2*pi*8) + (8*2*pi*7) = 1648*pi
• 9 years agoHelpfull: Yes(18) No(1)
• 4(2*pi*7+24*2*pi*8)=1592*pi
• 11 years agoHelpfull: Yes(10) No(18)
• 4days means total 8 circles
  distance covered by long hand for circle is 2*pi*8
  distance covered by short hand for circle is 2*pi*7
  total distance=8(2*pi*8+2*pi*7)=754.28
  
• 11 years agoHelpfull: Yes(6) No(11)
• why 24 comes explain???
• 11 years agoHelpfull: Yes(2) No(0)
• is that correct answer @kamlesh kumar ??????
  i think answer is 2880 pi
• 11 years agoHelpfull: Yes(0) No(2)
• 2261.76 i think.
• 11 years agoHelpfull: Yes(0) No(0)
• Example Problem
  
  Short Hand
  
  One full rotation in 12 hours ⟹2πr=16π⟹2πr=16π cm traversed every 12 hours.
  
  For one day, we have 32π32π cm, twice that of a 12 hour period.
  
  For 3 days, we then have 3⋅32π=96π3⋅32π=96π cm traversed.
  
  Long Hand
  
  One full rotation in 1 hour ⟹2πr=24π⟹2πr=24π cm traversed every hour.
  
  For one day, we have 24⋅24π=57624⋅24π=576 cm.
  
  For 3 days, we then have 3⋅576π=1728π3⋅576π=1728π cm traversed.
  
  Total Distance
  
  For the total, we have 96π+1728π=1824π96π+1728π=1824π cm.
• 9 years agoHelpfull: Yes(0) No(0)