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If three people can do a piece of work in 36 days. And first and second can do twice as the third. First and third can do thrice the second. Then find hopw many days will c take to do the work.
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- a+b+c=1/36
a+b=2c
2c+c=1/36
3c=1/36
c=1/108
c takes 108 days - 11 years agoHelpfull: Yes(47) No(1)
- Since A,B,C ca n do the work in 36 days.And the efficiency of (A+B) is twice to that of C .Hence we can take it as the efficiency of all the three will be equal.(See this can not be taken as true case but can be taken as a favourable case )
So C alone can do it in 36*3=108 days - 11 years agoHelpfull: Yes(9) No(0)
- a=b=c
108 days - 11 years agoHelpfull: Yes(1) No(6)
- it taks 72 days
2a = 2b=c
put in a+b+c=1/36
- 11 years agoHelpfull: Yes(0) No(9)
- c can do it in 96 days
- 11 years agoHelpfull: Yes(0) No(10)
- is the answer 98 ?
- 11 years agoHelpfull: Yes(0) No(13)
- c takes 108 days
- 11 years agoHelpfull: Yes(0) No(0)
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