Two tangents are drawn from a point outside the circle at a distance of 8cm from the centre of the

As given that it a tangent ... it indicates that it makes 90 degrees at point where it touches the circle..and 2 tangents originate from same point...thus forming 2 right angled triangles...hence the answer would be sqrt(8^2-2^2)=sqrt(60)=7.74
11 years agoHelpfull: Yes(3) No(0)
8^2-2^2=60
ans=sqrt(60)
11 years agoHelpfull: Yes(2) No(1)
the distance 8 will be the hypotenuse and 2 will be the base(radius)
so applying Pythagoras theorem
8^2=2^2+x^2
64=4+x^2
so x=root60(length of tangent)
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length of tngent = sqrt(60)+sqrt(60)=15.49cm
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sqrt(64-4)=sqrt(60)
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sqrt(8^2-2^2)=sqrt(60)
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60 is the answer
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angle between tangent and radius where tangent touches circle always 90 degree.
therefore,length=sqrt(64-4)=7.74
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r = 2;
h=8;
length = sqrt(8^2-2^2)

http://www.flashsandy.org/topics/fighting
11 years agoHelpfull: Yes(0) No(3)
Tangents drawn to a circle from an external point are equal in length.Now applying pythagoras theorem we get lenth of tangent=7.74cm
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sqrt(d^2-r^2)
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sqrt(8^2-2^2)=7.745
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Two tangents are drawn from a point outside the circle at a distance of 8cm from the centre of the circle whose radius is 2cm.find the length of the tangent