N!is having 37 zeroes at its end.How many possible values of N are possible ??

• To count the no of zeroes we have to count the no of 5present in them and we will calculate it as...
  100! = 100/5 + 100/25 =24zeroes
  and 150! = 150/5 + 150/25 + 150/125 = 37zeroes
  and 155! will have 38factors thus we can say that there are 5such values from 150! to 154!
• 11 years agoHelpfull: Yes(43) No(5)
• 150!,151!,152!,153!,154! ..... 4 possible vales of n. after 154!..155! will have 38 zeros
  
• 11 years agoHelpfull: Yes(6) No(9)
• ans-5
  160!-164!
• 11 years agoHelpfull: Yes(0) No(11)
• how this??
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  http://www.flashsandy.org/topics/fighting
• 11 years agoHelpfull: Yes(0) No(8)
• 150! to 154 !
• 11 years agoHelpfull: Yes(0) No(0)
• Ans:-5
  150! = 150/5 + 150/25 + 150/125 = 37zeroes
  so 150 to 154, 5 values are possible.
  for 155! there are 38 zeros.
• 11 years agoHelpfull: Yes(0) No(0)