Ten horses are numbered 1, 2, 3....10.The probability of winning of horse 1 is 1/8. The probability of winning of horse 2 is 1/7 and probability of winning of horse 3 is 1/5. What is the probability of any one of these horses to win the race?

• P(H1)=1/8 P(H1')=7/8
  P(H2)=1/7 P(H2')=6/7
  P(H3)=1/5 P(H3')=4/5
  
  P(W)=HORSE1 WIN (OR) HORSE2 WIN (OR) HORSE3 WIN
  =(1/8)(6/7)(4/5) + (7/8)(1/7)(4/5) + (7/8)(6/7)(1/5)
  =47/140
• 10 years agoHelpfull: Yes(32) No(0)
• 1/8+1/7+1/5= 131/180
• 10 years agoHelpfull: Yes(2) No(3)
• since there are 10 horse we have to consider probability of not winning any three horses 1-((1/8)+(1/7)+(1/5))=49/180
  p(w)=h1 win or h2win or h3 win
  =(1/8)(6/7)(4/5)(131/180) or continue
• 10 years agoHelpfull: Yes(2) No(0)
• P= 1/8+1/7+1/5, it canit be like 1/8)(6/7)(4/5) + (7/8)(1/7)(4/5) + (7/8)(6/7)(1/5), as in a race only one wins, so if H1 wins then we r sure that H2,H3 as well as all other horses looses so we dont need to mention them.
• 10 years agoHelpfull: Yes(0) No(0)
• (1/8)+(1/7)+(1/5)=0.4678 OR 131/280
• 9 years agoHelpfull: Yes(0) No(1)