a,b,c,d,e are distinct numbers. If (75-a) (75-b) (75-c) (75-d) (75-e) =2299.
Then a+b+c+d=?
Hint(as given): 2299 is divisible by 11.

• given 2299,
  2299= 11 * 11 * 19
  = 11 * 11 * 19
  = 11 * 11 * 19 * 1 * 1 (we can assume)
  so,
  2299= 11 * (-11) * 19 * (-1) * 1 (there is no change in result )
  now u will understood y im writing like that,
  2299 = (75-64)*(75-86)*(75-56)*(75-76)*(75-74) (because here a,b,c,d,e are distinct )
  so,i think the qstn should be
  a+b+c+d+e = 64+86+56+76+74 = 356
• 11 years agoHelpfull: Yes(44) No(1)
• 2299=11*11*19*1*1=(75-64)+(75-64)+(75-56)+(75-74)+(75-74)
  a+b+c+d=64+64+56+74=258(ans)
• 10 years agoHelpfull: Yes(1) No(2)