If average temperature of June, July and august is 31, and July, august, September is 30. Find temperature of September if temperature of June is 29?

• june+july+aug=93
  29+july+august=93
  july+aug=93-29=64
  given,july+aug+september=90
  64+septmbr=90
  september=90-64=26
• 11 years agoHelpfull: Yes(29) No(1)
• june=29
  (29+july+aug)/3=31
  july+aug=64
  (july+aug+sep)/3=30
  july+aug=64
  sep=90-64=34
• 11 years agoHelpfull: Yes(3) No(9)
• Assume temperatures of June, July,August, September be a, b, c, d.
  From the data
  (a+b+c)/3 =31
  》》》 a+b+c=93.--------(1)
  (b+c+d)/3 = 30
  》》》 b+c+d=90.-------(2)
  We also have temp of June to be 29. I.e a=29.
  Therefore, Substituting in first eqn.
  We get b+c =93-29 =64.
  Now substituting b+c =64 in second eqn , we get
  64+d=90
  》》》 d=26
  Therefore, temperature of September is 26.
• 9 years agoHelpfull: Yes(1) No(0)
• 24ans:
  x+y=64
  x+y+z=90
  z= sept
  x=july
  y=august
  
• 9 years agoHelpfull: Yes(0) No(1)
• sum of temp of june july and august=93
  sum of temp of july august sept=90
  subtract both d eq
  we get,,june-sept=3
  29-sept=3
  sept=29+3=32
• 9 years agoHelpfull: Yes(0) No(1)
• total temp. in june,july,aug=31*3=93
  total temp. in jul,aug,sep=30*3=90
  temp. in jun,jul,aug-temp.in june=93-29=64=>temp in jul and aug
  temp in jul,aug,sep-temp in jul and aug=90-64=26==>temp in sep
• 9 years agoHelpfull: Yes(0) No(0)
• oh,,sorry ,,my previous solution,i made a mistake in last eq...its
  sept=29-3=26
• 9 years agoHelpfull: Yes(0) No(1)