If 3 dices are rolled and a,b,c is obtained what is the probbability that a*b+c is even?

• 1/2
  outcome of a*b+c=even is
  1) even+even
  2)odd +odd
  
  for 1) to happen i.e even+even
  a*b= even and c=even
  a*b =even has two case a) even*even and b)odd*even
  hence a*b+c=even has 3 cases
  
  a)a=even b=even c=even prob=1/8
  b) a=odd b=even c=even///prob=1/8
  c)a=even b=add c=even prob =1/8
  total here =3/8
  
  2) second case is
  a*b+c=even
  a*b is odd and c=odd
  for a*b=odd only one case,
  a=odd b=odd
  hence this case is
  a=odd b=odd and c=odd
  prob=1/8
  
  hence total prob= 3/8+1/8=4/8=1/2
• 11 years agoHelpfull: Yes(9) No(1)
• case 1: a,b,c is even
  case 2: a is odd, b&c is even
  case 3: a&c is even,b is odd
  case 4:a,b,c is odd.
  
  each case will have 27 outcomes
  therefore, P=(27*4)/216
  P=1/2
• 11 years agoHelpfull: Yes(7) No(1)
• probability=3/8
• 11 years agoHelpfull: Yes(2) No(4)
• the possibilities are either "both a*b and c" are odd or "both a*b and c" are even. Taking this into account I got the ans to be 135/216 ie. 5/8
• 11 years agoHelpfull: Yes(0) No(3)
• @rohit kalita :explain it clearly........
• 11 years agoHelpfull: Yes(0) No(0)