Two parallel chord of length 32 and 24 cm and radius of circle is 20cm find the distance between the

ans will be 28.
10 years agoHelpfull: Yes(3) No(2)
28 cm is the ans.
using pythagorus theorem.
root(20^2-16^2)+root(20^2-12^2)=28.
10 years agoHelpfull: Yes(3) No(1)
construct right triangles...
let dist be 'x'
as chords divide equally,
20^2=(x1^2)+(16^2)
x1=12
similarly,
20^2=(x2^2)+(12^2)
x2=16
dist=x=x1+x2=12+16=28cm
10 years agoHelpfull: Yes(1) No(0)
if both chord lie in same semicircle then answer is 4
if two chord lie on either side of diameter answer is 28
10 years agoHelpfull: Yes(1) No(0)
according to r^2=h^2+a^2
ans is:28
10 years agoHelpfull: Yes(0) No(0)
chord is divided equally
10 years agoHelpfull: Yes(0) No(0)
plz can any 1 explain....
10 years agoHelpfull: Yes(0) No(0)
mohammad can u elaborate?
10 years agoHelpfull: Yes(0) No(0)
the answer depends on the position of the chords... my answer is 2 cm
10 years agoHelpfull: Yes(0) No(1)
what is chord actually,,,sorry guyz i can not understand even question then how can i understand your solutions
8 years agoHelpfull: Yes(0) No(0)

Two parallel chord of length 32 and 24 cm .and radius of circle is 20cm find the distance between the chords.