A is moving towards Bombay from Delhi and B is moving towards Delhi from Bombay . Speed of A is 50 km/hr and B 60 km/hr. When A and B meets B travel 120 KM more than A . find the time after they meet.

• let distance of A is xkm then B is x+120km
  s=d/t => s1/d1=s2/d2 => 50/x = 60/(x+120)
  5x+600=6x =>x=600km
  time taken t=d/s => t=600/50=12hours.
• 10 years agoHelpfull: Yes(23) No(1)
• simply by relative velocity concept
  time=distnc/reltv velocty
  =120/10
  =12hours
• 10 years agoHelpfull: Yes(19) No(5)
• let x be the distance travelld by A.
  time taken by A = time taken by B
  50/x=60/(120+x)
  on solving we get x=600 km.
  hence we can find out the time by (600 km)/(50 km/hr) or (720 km)/(60 km/hr)
  hence ans will be 12 hr
• 10 years agoHelpfull: Yes(7) No(0)
• 12hrs
  first 2hrs A moves 100 B moves 120
  when it comes 12th hr distance become600 and 720.
• 10 years agoHelpfull: Yes(3) No(0)
• ans is 12 hrs.
  
  Assume distance covered by A is x
  Then distance covered by B is x+120.
  By using s=d/t(t const).
  s1/s2=d1/d2.(speeds given).
  We get the value of x=600.
  By using this we can cal time=d/s=600/50=12hrs.
  
• 10 years agoHelpfull: Yes(2) No(0)
• ans- 12hr
  A/Q let A travels x km.
  so B travels x+120
  so (x/50)=(x+120)/60
  => x=600
  so time=600/50=12 hr
• 10 years agoHelpfull: Yes(1) No(0)
• the distance traveled by B = 50x+120 = 60x (x hours)
  which gives x=12 hours
• 10 years agoHelpfull: Yes(0) No(0)
• After 12 hours
  
• 9 years agoHelpfull: Yes(0) No(0)