A number when divided by 357 give 5 as remainder. Find the remainder when that no. is divided by 17.

• ans-5
  becoz 357 is divisible by 17 so it will produce same remainder
• 10 years agoHelpfull: Yes(9) No(0)
• num=357*x+5;
  num=17(21*x)+5;
  so no when divided by 17 gives 5 as remainder
  
  
• 10 years agoHelpfull: Yes(5) No(0)
• num is dividend= divisor*quotient+rem
  num=(357*q+5)-> eq1 on dividing with 357 rem is 5
  => (357*q+5)/357=5 => (357*q/357) +(5/357)= 5
  => q=5-(5/357)
  q=(1780/357) on substituting this in eq1 we get num=1785 which is divisible by 357, to get rem=5 we add +5 to it =>num is 1790.
  1790/17 gives rem 5.
  
• 10 years agoHelpfull: Yes(2) No(1)
• 5 is the ans..........
  let no.is=357*y+5 now it is divided by 17 we get 5 as a remainder
• 10 years agoHelpfull: Yes(1) No(0)
• ans is 5
  the first minimum number which gives 5 is 362
  when this is divided by 17 we'll get same remainder as previous.
• 10 years agoHelpfull: Yes(1) No(0)
• let the no is X. so a/q X=357*n+5. so when we divide it by 17 then
  x/17=(357*n+5)/17
  =(21*17*n+5)/17
  =21*n+ 5/17
  so reminder will be 5
• 10 years agoHelpfull: Yes(1) No(0)
• same remainder 5 as 357 is exactly divisible by 17
• 10 years agoHelpfull: Yes(1) No(0)
• number= 357*k+5 where k is the quotient when divided by 357. now 357*k is perfectly divided by 17 and hence the remainder is 5
• 10 years agoHelpfull: Yes(1) No(0)
• x/357=5
  x=1785
  
  1785/17=105
• 10 years agoHelpfull: Yes(0) No(2)
• 357/7=21
  so the number gives same remainder when that number is devided by 7.
• 10 years agoHelpfull: Yes(0) No(1)
• its simple..
  357 |_x___
  1 -5
  to find the number : x= 357*1 + 5 =362
  so 362/17= 5 ans:5
• 10 years agoHelpfull: Yes(0) No(0)
• 357 is multiples of 17. so it has 5 asa remainder so 17 also get 5 as a remainder....so ans is 5
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 5.
  no=357(x)+5.
  By keeping x the no can be found out.
  In all cases the rem is 5.
• 10 years agoHelpfull: Yes(0) No(0)
• 357is divisible by 17 so is remainder
• 10 years agoHelpfull: Yes(0) No(0)
• Let the number be x
  then x=(quo*357)+5
  if quo=1
  then x= (357)+5 = 362
  362%17 = 5
  so the answer is 5
  
• 10 years agoHelpfull: Yes(0) No(0)
• Ans: 5
  
  let the quotient be x.
  then x*357+5 is the dividend. so,
  (x*357+5)/17 gives 5 as remainder since 357 is evenly divisible by 17.
  
• 10 years agoHelpfull: Yes(0) No(0)