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Arithmetic
. If A=2/3(B-C) and c=1/2(A+B) and A+B+C=3000, then find C.
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- c=3000-(a+b)
we know that , c=1/2(a+b) ---> 2c=a+b
c=3000-2c
c=1000 - 10 years agoHelpfull: Yes(34) No(4)
- C=1/2(A+B)--> 2C=A+B eqn1
A+B+C=3000--> A+B=3000-C eqn2
PUTTING VALUE OF eqn2 IN eqn1
2C=3000-C
3C=3000
C=1000 WHICH IS ANSWER :) - 10 years agoHelpfull: Yes(2) No(3)
- Guys its not that...
A=2/3(B-C).
Thus 2C != (A+B)... - 10 years agoHelpfull: Yes(1) No(2)
- c=1/2(a+b) ->eqn1
a+b+c=3000 ->eqn2
multiply eqn 2 by 1/2...
=>1/2(a+b+c)=1/2(3000)
=>1/2(a+b)+1/2(c)=1500
=>c+1/2(c)=1500
=>3/2(c)=1500
=>c=1000 - 10 years agoHelpfull: Yes(1) No(1)
- c=1/2(A+B)
A+B=2C
A+B+C=3000
c=3000-2C
3C=3000
c=1000
- 10 years agoHelpfull: Yes(1) No(0)
- value of c is 1000...by solving 3 equations
- 10 years agoHelpfull: Yes(1) No(0)
- 2c=a+b. so c=3000-(a+b)
so 3c=3000
c=1000 - 10 years agoHelpfull: Yes(0) No(1)
- it's answer will be 1000
- 10 years agoHelpfull: Yes(0) No(2)
- 3000 is the answer
- 10 years agoHelpfull: Yes(0) No(2)
- 1000.a+b=2c.so 3c=3000
- 10 years agoHelpfull: Yes(0) No(2)
- a+b+c=3000
c=1/2(a+b)
then a+b=3000-c
c=1/2(3000-c)
c=1000
- 10 years agoHelpfull: Yes(0) No(1)
- A=2/3B _(1)
B=C _(2)
C=1/2(A+B)_(3)
A+B+C=3000_(4)
from (2) we get:
2C=A+B
on keeping this value in (4) we get:
2C+C=3000
or C=1000 - 10 years agoHelpfull: Yes(0) No(0)
- answer is 1000
- 10 years agoHelpfull: Yes(0) No(0)
- ans is 1000
- 10 years agoHelpfull: Yes(0) No(0)
- 1000 is the value of c.
- 10 years agoHelpfull: Yes(0) No(0)
- simply put a+b=2c in a+b+c=3000 enough
- 6 years agoHelpfull: Yes(0) No(0)
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