. If A=2/3(B-C) and c=1/2(A+B) and A+B+C=3000, then find C.

• c=3000-(a+b)
  we know that , c=1/2(a+b) ---> 2c=a+b
  c=3000-2c
  c=1000
• 11 years agoHelpfull: Yes(34) No(4)
• C=1/2(A+B)--> 2C=A+B eqn1
  A+B+C=3000--> A+B=3000-C eqn2
  PUTTING VALUE OF eqn2 IN eqn1
  2C=3000-C
  3C=3000
  C=1000 WHICH IS ANSWER :)
• 11 years agoHelpfull: Yes(2) No(3)
• Guys its not that...
  A=2/3(B-C).
  Thus 2C != (A+B)...
• 11 years agoHelpfull: Yes(1) No(2)
• c=1/2(a+b) ->eqn1
  a+b+c=3000 ->eqn2
  multiply eqn 2 by 1/2...
  =>1/2(a+b+c)=1/2(3000)
  =>1/2(a+b)+1/2(c)=1500
  =>c+1/2(c)=1500
  =>3/2(c)=1500
  =>c=1000
• 11 years agoHelpfull: Yes(1) No(1)
• c=1/2(A+B)
  A+B=2C
  A+B+C=3000
  c=3000-2C
  3C=3000
  c=1000
  
• 11 years agoHelpfull: Yes(1) No(0)
• value of c is 1000...by solving 3 equations
• 11 years agoHelpfull: Yes(1) No(0)
• 2c=a+b. so c=3000-(a+b)
  so 3c=3000
  c=1000
• 11 years agoHelpfull: Yes(0) No(1)
• it's answer will be 1000
• 11 years agoHelpfull: Yes(0) No(2)
• 3000 is the answer
  
• 11 years agoHelpfull: Yes(0) No(2)
• 1000.a+b=2c.so 3c=3000
  
• 11 years agoHelpfull: Yes(0) No(2)
• a+b+c=3000
  c=1/2(a+b)
  then a+b=3000-c
  c=1/2(3000-c)
  c=1000
  
• 11 years agoHelpfull: Yes(0) No(1)
• A=2/3B _(1)
  B=C _(2)
  C=1/2(A+B)_(3)
  A+B+C=3000_(4)
  from (2) we get:
  2C=A+B
  on keeping this value in (4) we get:
  2C+C=3000
  or C=1000
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 1000
• 11 years agoHelpfull: Yes(0) No(0)
• ans is 1000
• 11 years agoHelpfull: Yes(0) No(0)
• 1000 is the value of c.
• 11 years agoHelpfull: Yes(0) No(0)
• simply put a+b=2c in a+b+c=3000 enough
• 7 years agoHelpfull: Yes(0) No(0)