In how many rearrangements of the word ERASED in the letter 'A' positioned in between the 2 'E's?

• 24
  we make group of EAE as per given question
  then now we have 4 letters so it can permute by 4! ways so ans is 24
• 11 years agoHelpfull: Yes(15) No(10)
• 4!
  Two E's can be arranged in 1 way only(because Identical letters: [2!/2!])
  then A can be arranged in between E's is oneway.
  These (EAE) treated as one group(letter).
  Remaining letters(RSD)& That group(letter) =4.
  So Four Letters can be arranged in 4places can be done in 4! ways
  
• 11 years agoHelpfull: Yes(14) No(6)
• ans is 120
  
  A _ _ _ _ _ = 5! = 120 arrangements
  
  121 term is EAEDRS. which is the term we needed.
• 11 years agoHelpfull: Yes(10) No(12)
• (EAE)_ _ _ 4!*3!/2!= 72
• 11 years agoHelpfull: Yes(10) No(20)
• case1:E _ _ _ _ E => 4!=24 (A can be any where in 3 blanks)
  case 2:E _ _ _ E _ =>3*3!*2=36 (A can be in 3 blanks in b/w so can be arranged in 3 ways remaining 3 letters can be arranged by 3! and 2 ways of arranging E's)
  case 3: E _ _ E _ _ =>2*3!*3=36
  case 4: => E _ E _ _ _ => 4*3!=24
  
  
  24+36+36+24=120
• 11 years agoHelpfull: Yes(10) No(2)
• ans will be 24.. EAE take as a single word than apply rearrangement...
• 11 years agoHelpfull: Yes(8) No(7)
• ans is 48 bcz
  EAE_ _ _ 3!=12 WAYS
  _EAE_ _ 3!=12 WAYS
  _ _ EAE_ 3!=12 WAYS
  _ _ _EAE 3!=12WAYS
  12+12+12+12=48ANS
• 11 years agoHelpfull: Yes(8) No(13)
• it will be 2*4!
  RSD(EAE)
• 11 years agoHelpfull: Yes(4) No(5)
• 6C3*3!=120
• 11 years agoHelpfull: Yes(4) No(2)
• 4!*(2!*2!)=4!
• 11 years agoHelpfull: Yes(4) No(2)
• case 1: E A _ _ _ _ (A in 2nd)=> 4!=24
  case 2: _ _ _ _ A E (A in 5th)=> 4!=24
  case 3: E _ A _ _ _ or _ E A _ _ _ (A in 3rd)=>3(any one from R,S,D)*3!(remaining 3 alphabets in 3 pos)+ 3*3!=36
  case 4: _ _ _ A _ E or _ _ _ A E _ (A in 4th)=>(same as case 3)=36
  
  total= 24*2 + 36*2=120 ways
• 11 years agoHelpfull: Yes(4) No(0)
• according to ques arrangements can be made like(EAE)RSD..and a block of EAE and RSD can be rearranged.EAE has arrangements of 3!/2! =3 and whole (EAE)RSD can be arranged with above condintion in 4! ways=24.thus total ways =24*3=72 ans
• 11 years agoHelpfull: Yes(3) No(5)
• ans:74
  (EAE)RSD
  for EAE it can be arrange in 3!/2! ways=3
  so whole can be arranged in (4*3*2*1)*3=72 ans
• 11 years agoHelpfull: Yes(3) No(5)
• 145
  DEAERS
  A _ _ _ _ _=120
  D A _ _ _ _=24
  D E A E R S=120+24+1
• 11 years agoHelpfull: Yes(2) No(7)
• ------.
  A cannot be placed on the 2 extremes .
  So A must be placed on the remaining 4 internal positions. that can be done in 4P1=4 ways.
  now there are 2 E's.the E's must be placed on either side of A.that can be done in only 1 way.
  so there are still 3 places vacant after placing EAE. these remaining 3 places can be filled using the 3 remaining letters in 3! ways.
  So total arrangements possible = 4 * 1 * 3! = 24
• 11 years agoHelpfull: Yes(2) No(1)
• its 6!(2!*3)=120
  because 6 letters can be arranged in 6!ways , but in this case we have 2E's thus total no of ways wud be (6!)/2!. Now the constaint we are left with is is "A shoul be positioned b/w 2 E's) . in all such arrangements A would be either to the left of both the E's or to the right of both the E's or in between them , now these three events are equally likely therefore total no of ways wud be 6!/(2!*3)
  
• 11 years agoHelpfull: Yes(1) No(1)
• ERASED: RSD+(EAE) =3+1 = 4!
  EAE =2!/2! = 1
  total ways = 1*4!=24
  
  
• 11 years agoHelpfull: Yes(1) No(0)
• Ans:- (6c3 * 1)* 3! = 120
  6c3 is for selecting three position for EAE and they can placed in only 1 way.
  Remaining 3 letter can be arranged in 3! ways.
• 11 years agoHelpfull: Yes(1) No(0)
• A... 5!/2!= 60
  DA...4!/2!= 12
  DEAE..2!= 2
  60+12+2= 74
• 11 years agoHelpfull: Yes(0) No(5)
• ans will be 4!*2
  =48
• 11 years agoHelpfull: Yes(0) No(3)
• 7!/(2*2!)=210
• 11 years agoHelpfull: Yes(0) No(2)
• eae can be arranged in 4ways...rsd each can be arranged in 3! ways.4*3*3!=72ways
• 11 years agoHelpfull: Yes(0) No(4)
• 144 arrangements
  assume EAE as a one letter remaning letters are 3 total 4 letters we have.
  by permutation there are 4! ways of arranging them =24
  and EAE can be arranged in 3! ways =6
  24*6=144
  
• 11 years agoHelpfull: Yes(0) No(1)
• 24 ways !!!
• 11 years agoHelpfull: Yes(0) No(0)