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A,B,C can do a work in 36 days A,B is twice as efficient as C.
B,C is thrice efficient as A. In how many days can C alone do a work?
Read Solution (Total 6)
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- A+B+C can do 1/36 units of work in 1 day
A+B=2C
A+B+C=1/36
2C+C=1/36
C=1/108
hence C alone can do in 108 days - 11 years agoHelpfull: Yes(36) No(1)
- 108 days is right ans:
1/A+1/B+1/C=1/36;
1/A+1/B=2/C;
so
2/C+1/C=1/36;
c=108; - 11 years agoHelpfull: Yes(5) No(1)
- a+b+c=36 days-------eq1
a+b=2c(given)-------eq2
put 2c in eq 1, we get
2c+c=36
3c=36 and c=12ans - 11 years agoHelpfull: Yes(2) No(9)
- A+B+C can do 1/36 units of work in 1 day
A+B=2C
A+B+C=1/36
2C+C=1/36
C=1/108
hence C alone can do in 108 days - 11 years agoHelpfull: Yes(2) No(0)
- i think its 180 if a=2c,b=2c
Else 108 is correct answer !!! - 11 years agoHelpfull: Yes(1) No(0)
- ans is 12...
- 11 years agoHelpfull: Yes(0) No(5)
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