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There are 4 boys and 5 girls in two separate queues. Two separate queues are merged so that the position of the boys (in relation to each other) and those of girls (in relation to each other) remain unchanged. In how many ways this can be done?
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- only two way as the position of girls and boys with respect to each must remain unchanged ....so the only way is to append them...
- 10 years agoHelpfull: Yes(15) No(2)
- let boys are=b1,b2,b3,b4
arangement of boy=4!
and girls are=g1,g2,g3,g4,g5
arangement of girls=5!
arangement of boys and girls without change in relation=2!*4!*5!
- 10 years agoHelpfull: Yes(6) No(9)
- let the sequence of girls be
_g_g_g_g_g_
so there are 6 place where boys can be placed
ans is 6c4+3*(6c3)+3*(6c2)+6c1
because they can be grouped as 1-1-1-1,1-1-2,2-2, 1-3, 3-1, 4... - 10 years agoHelpfull: Yes(4) No(6)
- i thinkanother solution can b
let abcd boys
pqrs girls
ways can b
abcdpqrs
dcbapqrs
pqrs abcd
pqrs dcba
similarily the girls can b arraanged in 4 ways
therefore total 8ways - 10 years agoHelpfull: Yes(4) No(2)
- ans is 360
- 10 years agoHelpfull: Yes(2) No(1)
- _g_g_g_g_g_
6 gaps
boys can select their places bt they cant arrange
6c4+6c3+6c2+6c1+6c0 ans - 10 years agoHelpfull: Yes(1) No(4)
- first girls are arranged in 9c5 ways and remaining 4 places are arranged with boys in 4c4 ways. so 9c5*4c4=126
- 10 years agoHelpfull: Yes(1) No(1)
- 1st boys queque ahead the girl queque
2nd girls are ahead so only two way - 10 years agoHelpfull: Yes(1) No(0)
- a+b+c+d+e = 5
9C5 ways.. - 5 years agoHelpfull: Yes(0) No(0)
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