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A and B run a 1km race. If a gives B a start of 50m, a wins by 14 seconds and if A gives B a start of 22 seconds, B wins by 20 meters. Find the time taken by A to run 1km.

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a/b=1000/(950−14b)=980/(1000−22b)
50,000 -1100b = 46550 -686b
Solving we get b = 25/3
Now Assume A's speed = x
1000/(950−14(25/3))=x/(25/3)
x = 10
So x takes 1000/10 = 100 seconds.
11 years agoHelpfull: Yes(12) No(4)

100 seconds perfect answer !!!
11 years agoHelpfull: Yes(0) No(1)

TCS Other Question

What will be the last two digits of (5306)^214 W,X,Y,Z are integers. The expression X - Y - Z is even and the expression Y - Z - W is odd. If X is even what must be true.
option
A) W must be odd.
B) Y - Z must be odd.
C) Z must be even.
D) Z must be odd.