Find last two digit of the following expression. (201*202*203*204*206*207*208*209)^2

• last two digits are 76....
  product of 2 digits (01*04*09*16*36*49*64*81)=********76
• 11 years agoHelpfull: Yes(33) No(13)
• product of last two digit=(01*02*03*04*05*06*07*08*09)=362880
  last two digit of (362880)^2=00
• 11 years agoHelpfull: Yes(9) No(24)
• @anubhav:their is not 205 in the question so 00 will not be the last two digit the last two digit will be 76 as explained by utkarsh
  
• 11 years agoHelpfull: Yes(3) No(6)
• 00 are the last 2 digits
• 11 years agoHelpfull: Yes(1) No(11)
• product of last two digit=(01*02*03*04*05*06*07*08*09)=362880
  last two digit of (362880)^2=
  80^2
  last second digit is=(8*2=16)=6
  and last digit is=(0^2)=1
  thus last two digit is=61
• 11 years agoHelpfull: Yes(1) No(7)
• ans is 70
  
• 11 years agoHelpfull: Yes(1) No(1)
• 76 are the two last digits !!!
• 11 years agoHelpfull: Yes(1) No(0)