Sum of the digits of a three digit number is 17 and sum of the squares of the digit is 109. Also when the number is subtracted by 495 the number gets reversed. Find the number

• let the no. be abc
  now, a+b+c=17
  a^2+b^2+c^2=109
  and 100a+10b+c-495=100c+10b+a
  ie.a-c=5
  conisdering the cases for a and c(9,4..,8,3....,7,2....6,1)
  we get value of a and c as 8,3 therefore b=6..i.e. no=863
• 11 years agoHelpfull: Yes(30) No(3)
• Let the digits are x,y,z.
  one number xyz.
  sum of the digits of a three difit number=x+y+z=17
  so, by considering x=8, y=6 and z=3.
  x+y+z=8+6+3=17
  Now Square, 8^2+6^2+3^2=64+36+9=109.
  Subtracting by 495 we get 368 as a reversed number.
  so the answer is 863.
  
• 11 years agoHelpfull: Yes(16) No(6)
• answer is 863
• 11 years agoHelpfull: Yes(7) No(3)
• x=8;y=6;z=3; x+y+z=17; x^2+y^2+z^2=64+36+9=109; 863-495=368... so the number is 863..
• 11 years agoHelpfull: Yes(3) No(2)
• let the number be xyz
  give that x+y+z=17
  x^2+y^2+z^2=109
  100x+10y+z-495=100z+10y+x
  on solving we get x=8,y=6,z=3
  so xyz is 863
• 11 years agoHelpfull: Yes(0) No(0)
• Number is 863 !!!
• 11 years agoHelpfull: Yes(0) No(0)