There are 80 litres of milk in a vessel. 8 litres milk are drawn off and equal quantity of water is added. The same operation is repeated for a second and a third time. Find the quantity of milk in the resultant mixture.

• amount of milk left after 3 operations:[80(1-8/80)^3]=80*9/10*9/10*9/10=58.32lts
• 11 years agoHelpfull: Yes(34) No(4)
• there is a formula for solving this problem
  X*(1-Y/X)^n
  where X=initial quantity(here it is 80)
  Y=replaced quantity(here it is 8)
  n=number of times it is being replaced(here it is 3)
  therefore,resultant=80*((1-8/80)^3)
  =58.32
• 11 years agoHelpfull: Yes(25) No(0)
• since water and milk are mixed,10% draw of mix=(10%draw of milk)+(10%draw of water)
  1st take=10% of milk [8/80*100=10]
  remaining milk=80-8=72
  2nd take=10% of milk
  remaining milk=72-7.2=64.8
  3rd take=10% of milk
  remaining milk=64.8-6.48=58.42
• 11 years agoHelpfull: Yes(12) No(3)
• i think its 56
  
• 11 years agoHelpfull: Yes(3) No(1)
• ans: 5:2
  applying aligation we get
  5/3-4/3=1/3
  4/3-1/2=5/6
  now
  5/6*3/1=5/2
• 11 years agoHelpfull: Yes(0) No(1)
• 58.07 liters
  Its d ans.
• 11 years agoHelpfull: Yes(0) No(1)
• ans= 67.32 Lt.
• 11 years agoHelpfull: Yes(0) No(2)
• amount of remaining 58.32 Ans.
• 11 years agoHelpfull: Yes(0) No(0)