A runs 4.3 times as fast as B. If A gives B a start of 45 m, how far must the winning post be so that A and B reach it at the same time.

• let distance covered by B=d
  then distance covered by A=d+45
  
  and let speed of B=x
  then speed of A=4.3x
  
  by equating for time= (d+45)/4.3x=d/x
  solving for d=13.63
  so winning post must be 13.63+45=58.63m from A
• 10 years agoHelpfull: Yes(56) No(3)
• A's speed=4.3x
  B's speed=x
  A's distance=45+x
  B's distancs=x
  time= d/S
  45+X/43.X=d/s
  and d is 13.63
  and a reaches is that 45+13.63=58.63
• 10 years agoHelpfull: Yes(11) No(0)
• 58.6m from a
  
• 10 years agoHelpfull: Yes(1) No(0)
• Nice Question !!!
  
  The winning post must be 58.63m away from A.
• 10 years agoHelpfull: Yes(0) No(0)