out of a pack of 52 cards one is lost,from the remainder of the pack,two cards are drawn and found to be spades.find the chance that the missing card is a spade.

• the probability that the missing card not a spade is 13c2/51c2..so,the required probability is 1-13c2/51c2
• 11 years agoHelpfull: Yes(2) No(0)
• let A b the event that missing card is spade
  B b the event that drawing 2 spades
  P(A/B)=probability of missing card is spade given that 2 spades are drawn=?
  P(B/A)=probability of drawing 2 spades given that missing card is spade=12c2/51c2
  P(A)=Probability of missing card is spade=13/52
  p(B)=probability of drawing 2 spades =13C2/52C2
  we know that P(A/B)=P(B/A)*P(A)/P(B)
  Substituting above values we get P(A/B)=11/50
• 11 years agoHelpfull: Yes(2) No(1)
• if the missing card is spade then probability will be
  12c2/51c2
  
• 11 years agoHelpfull: Yes(1) No(0)
• the problem can be treated as if we are selecting the third card out of the 50 remaining cards.
  
  11 of these are spade .
  so,11/50 is ans
  
  thanks :)
• 10 years agoHelpfull: Yes(0) No(0)