The dimensions of a open box are 50cm,40cm,23cm.It's thickness is 3cm if one cubic cm of metal used in the box weighs 0.5gms.Find the weight of the box?

• volume of cube = 50*40*23 = 46000
  volume of inner cube =(50-3-3)*(40-3-3)*(23-3-0)=29920
  so the volume of the metal = 46000-29920 = 16080 cm^3
  so the weight of the metal = 0.5 * 16080 = 8040 gms.
• 11 years agoHelpfull: Yes(50) No(6)
• faces with dimesion are {(50*40),(40*23),(50,23)}
  all dimesions have 2 faces but top one is not considerd
  so volume of the metal will be
  2(40*23+50*23)*3+40*50*3=18420 cubic cm
  total weight=18420*0.5 gms= 9210gms
• 11 years agoHelpfull: Yes(13) No(13)
• 1 cm cube weight is 0.5gm thus 24420cm cube has weight of???=24420*0.5=12210
  sory my mistake in privious answer
• 11 years agoHelpfull: Yes(2) No(7)
• I think the answer should be 8040 gms.
• 11 years agoHelpfull: Yes(2) No(0)
• Volume of the metal used in the box = External Volume - Internal Volume
  = [(50 x 40 x 23) - (44 x 34 x 20)]inline fn_jvn cm^3
  = 16080 inline fn_jvn cm^3
  
  Weight of the metal =[(16080 x 0.5)/1000] kg = 8.04 kg
• 9 years agoHelpfull: Yes(1) No(0)
• l=40,b=23,h=50
  total area=2(l*b+h*b+l*h)
  =2(40*23+50*23+50*40)
  
• 11 years agoHelpfull: Yes(0) No(13)
• sory my previous answer is incomplete
  l=40,b=23,h=50
  total area=2(l*b+h*b+l*h)
  =2(40*23+50*23+50*40)
  =8140 is total outer area of box
  but here 3cm widht of each wall thus it mean each area is extend 3 cm thus
  =8140*3
  =24420
  but now we want to use a one cubic bar to built that box which 1 bar is wight os 0.5gm thus for all box weight is
  =24420/0.5
  =48840
• 11 years agoHelpfull: Yes(0) No(10)
• Dimensions of box: Length=50cm,Breadth=40cm,height=23cm.
  Volume of box=50*40*23=46000 cc.
  now, density of metal=0.5g/cc (given)
  now, if metal is used, thickness of box is 3cm.
  
  therefore,new dimension or outer dimensions of box are:
  Length=56cm,Breadth=46cm,height=23cm
  therfore,volume=56*46*23=59248 cc.
  
  now metal will get concentrated in net volume=59248-46000=13248cc.
  
  thus,weight of box= density of metal* net volume=13248*0.5=6624 gms or 6.624 kg
• 11 years agoHelpfull: Yes(0) No(6)
• total volume of cube = 50*40*23 = 50600
  total volume of hollow cube = (50-6)*(40-6)*(23-6) = 44*34*17 = 25432
  total volume of metal = 50600-25432 = 25168 cm^3
  total weight = 25168*.5 = 12584gms :)
  
• 11 years agoHelpfull: Yes(0) No(1)
• I am really confused that why everyone is finding out the weight of the metal ..
  Wherein question you have to find out weight of the box. So , asking to someone to submit proper solution.
• 9 years agoHelpfull: Yes(0) No(1)