WHEN THE NUMBERS ARE WRITTEN IN BASE b, WE HAVEE 15*25=414 THEN THE VALUE OF bis.

• write 15*25=414 as
  
  (1*b^1+5*b^0)+(2*b^1+5*b^0)=(4*b^2+1*b^1+4*b^0)
  ===>
  (b+5)(2b+5)=4b^2+b+4
  ===> 2b^2-14b-21=0
  on solving we get roots as 8.2697 and -1.2697
  hence b~=8.26 or 8
• 11 years agoHelpfull: Yes(38) No(1)
• 15*25=(375) with base 10
  that is equal to 414 with base b
  so,
  4*b^2+1*b^1+4=375
  on solving
  b=9.5,-9.75
  ignoring -ve
  answer will be 9.5
• 11 years agoHelpfull: Yes(2) No(5)
• multiply the last two digits.. 5*5=25
  remainder[25/x]=last digit of 414.i.e 4
  x=7
• 11 years agoHelpfull: Yes(1) No(16)
• according to problem 15*25= 375
  and (414)base b =(4bˆ2+1*bˆ1+4*bˆ0)base 10= 375
  solving we get b=9.5 approx
  which does not seem to be a right answer.
  please check for any mistake in solution.
• 11 years agoHelpfull: Yes(1) No(1)
• sry...small correction....
  by solving 2b^2-14b-21=0 we will get 8.2,-1.2 as roots
  answer is 8(approx) not 13..
• 11 years agoHelpfull: Yes(1) No(1)
• write 15*25=414 as
  
  (1*b^1+5*b^0)+(2*b^1+5*b^0)=(4*b^2+1*b^1+4*b^0)
  ===>
  (b+5)(2b+5)=4b^2+b+4
  ===> 2b^2-14b-21=0
  on solving we get roots as 8.2697 and -1.2697
  hence b~=8.26 or 8
  
• 11 years agoHelpfull: Yes(1) No(0)
• ans: 10
  
  15*25=375
  then 375 is written in base 'b' as 414.
  
  then by verification base (414)10=375.
  so b=10
• 11 years agoHelpfull: Yes(0) No(0)
• let base be 'b' ,()b=base b,()10=base 10
  (15)b=(1*b+5*1)10=b+5
  (25)b=(2*b+5*1)10=2b+5
  (414)b=(4*b^2+1*b+4*1)10=4b^2+b+4
  (15)b*(25)b=(414)b
  (b+5)*(2b+5)=4b^2+b+4
  by solving above eq we get...b=-6.07,13.03
  ans=13(aprox)
  
  
• 11 years agoHelpfull: Yes(0) No(1)
• its 7 as u sees....
  
  if we assume its base 7 then , 5*5 = 34, 13 = 6 .... now do simple multiplication nd u vl get 414...
• 11 years agoHelpfull: Yes(0) No(2)
• b~=8.26 or 8
• 11 years agoHelpfull: Yes(0) No(0)
• the question should be 15*25 = 444
  then the value of b = 7
• 10 years agoHelpfull: Yes(0) No(0)