In how many ways one or more than one fruit, can be selected from 6 varieties of fruits given that there are 5 fruits of each variety?
option
a) 66
b) 56
c) 66-1
d) none

• pls explain
• 10 years agoHelpfull: Yes(28) No(2)
• 66-1 is the answer
• 10 years agoHelpfull: Yes(7) No(18)
• each fruit has 2 ways,either selected or not selected.there are six varieties of fruits each variety has 5 fruits.no of possible ways of slecting one or more fruits are (5+1)(5+1)(5+1)(5+1)(5+1)5+1) ways.but atleast one is to be selected in 46656-1 ways ie 46655 ways.ans is none
  
• 10 years agoHelpfull: Yes(7) No(0)
• 1 fruit can be selected in 6 ways
  2 fruits can be selected in 6c2 ways
  3 frts cn b selected in 6c3
  4 fruits cn b selected 6c4
  5 friuts cn b selectd in 6c5
  and all 6 friut in 1 ways;
  since here it asking how many we can select different no of fruits ...total fruits is avaible is 3o;but this is the minimum case of different selection of fruits ...no of ways sud be greater than 6+15+20+15+6+1=63;for seven fruits more than 66 would be there...so answer is none of the above
  
• 10 years agoHelpfull: Yes(1) No(4)
• each variety can be selected in 6 ways i.e, 0 or 1 0r 2 0r 3 0r 4 0r 5
  so from all the fruits we can select in 6*6=36 ways
  but this includes selection of no fruit...
  ans=36-1=35 ways
  ans:(d)none
• 10 years agoHelpfull: Yes(0) No(3)
• 6^6-1..because 5 fruits of 6 varities can be selected in 6 ways^6..and 1 case for no selection
• 10 years agoHelpfull: Yes(0) No(0)
• Lets consider the case of the first fruit. There are 5 fruits of the variety. We have to select either 0/1/2/3/4/5 of this varity of fruit. this can be done in 6 ways.
  Same is the case with each variety of fruit, it can be done in 6 ways.
  So, total 6 power 6. But we have to exclude the case of selection o fruits of each variety. This particular case must be excluded.
  
  So, total of (6^6)-1 ways. Choice (c)
• 10 years agoHelpfull: Yes(0) No(0)