. For which of the following ‘n’ is the number 2^74 + 2^2058 + 2^(2n) a perfect square ?

• given 2^74+2^2058+2^(2n)=2^(2*37)+2*2^37*2^n+2^(2*n) [a^2+2*a*b+b^2]
  from above we can write 2^2058=2*2^37*2^n=2^(1+37+n)
  since bases are equal powers are equal
  2058=1+37+n
  by solving we get n=2020
  
• 11 years agoHelpfull: Yes(24) No(0)