A and B travelling from x to y A starts at 12pm at a speed of 63m h B at

at 12pm A is at x...At 1:30pm he reaches 63*1.5m away from x
so,at 1:30pm dist bw A and B is 94.5m..B has to cover the 94.5m and also 34m ahead.
time taken=(94.5+34)/(84-63)=6.119hrs=6hrs 7min 10 sec
the time then is 7:37:10pm
11 years agoHelpfull: Yes(29) No(1)

speed of A=63m/h,A traveled distance=(d-34)m,A takes time=(t+1.5)hrs
speed of B=84m/h,B traveled distance=d m,B takes time =t hr
distance=speed*time
B--> d=84*t
A--> d-34=63*(t+1.5)
==>84t-34=63t+94.5
==>84t-63t=94.5+34
==>21t=128.5
==>t=128.5/21
==>t=6.11hrs
B be 34m ahead of A 6.11hrs after 1.30pm.
==> 7.41pm
11 years agoHelpfull: Yes(18) No(2)
6hrs 7min 9sec after 1:30P:M
11 years agoHelpfull: Yes(5) No(1)
let D be distance where A and B meet.
so (D-94.5)/63=D/84 => D=378m.
so at 378m distance from initial point,A and B will meet.
and B requires 378/84=4.5 hrs. to meet B.so now when A and B meet,time is 1.5 pm+4.5 hrs=6 pm.
now relative speed of B to A is 84-63=21.To cover 34 m with this speed B requires 34/21=1.6 hrs i.e. 1hr. 36 minutes. so now final answer is 6 PM +1 hr 36 minutes=7:36 PM.
11 years agoHelpfull: Yes(4) No(0)
ans is : 03:36 pm
11 years agoHelpfull: Yes(2) No(4)
A start 12pm at the speed 63m/h
1.30pm a reach 94.50m Now B start 84m/h
2.30 A reach 157.50 and B reach 84
3.30 A reach 220.50 and B reach 168
....
7.00 A reach 439.50 and B reach 471 m

7.05pm B be ahead of 34m of A
11 years agoHelpfull: Yes(2) No(0)
time = distance/(relative speed)
t=(94.5+34)/84-63
t=6.11
11 years agoHelpfull: Yes(2) No(0)
can any one explain in detail
11 years agoHelpfull: Yes(1) No(1)
07:37:14 pm
11 years agoHelpfull: Yes(1) No(0)
4:07 pm
11 years agoHelpfull: Yes(0) No(2)
B will be 34 minutes ahead of A, at 7:41 pm.
11 years agoHelpfull: Yes(0) No(0)

A and B travelling from x to y .A starts at 12pm at a speed of 63m/h .B at 1:30 pm at a speed of 84 m/h .at what time will B be 34m ahead of A