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Guys help me with these questions too plzz
1. In how many ways a team of 11 can be must be selected from 5 men and 11 women such that the team must not comprise of more than 3 men?
2. the perimeter of a square is equal to twice the perimeter of rectangle of length 8 cm and breadth 7 cm. what is the circumference of a semicircle whose diameter is equal to side of the square?
3. area of a quadrilateral whose vertices are (-1,1),(2,2),(2,-1), -2,-2)
4. speed of the train is 20 km/hr. The strength of steam was increased two fold but due to certain other factors the friction also increase 3/2 times. If in the beginning the ratio of strength of steam and friction was 3:1.Find present speed of the train.
5. Anu's ages was 3 times older to the age of banu's age 10 years ago.What will be the age of anu next year,if their present age ratio is 2:11?
6. Anju started to move in the direction of east and turn to his left after moving 25m. Then he turned to his left after moving 10 m and after this he moved 35 m. Then he turned to his left and moved 20 m. Now how far is he from his starting point?
Read Solution (Total 13)
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- Q1 >> 11C11 + (5C1 * 11C10) + (5C2*11C9) + (5C3*11C8)
- 11 years agoHelpfull: Yes(9) No(2)
- 1.3 men and 8 women::5c3*11c8=1650
2 men and 9 women::5c2*11c9=550
1 man and 10 women::5c1*11c10=55
11 women::1
total=2256
2.4s=2*2*(8+7)::s=d=15::15*3.14
3.10 sq units::use analytical geo formula
4.s-f=20::s=3f::s=30,f=10::2s-(1.5*f)=60-15=45
5.verify que once
6.10*1.414 - 11 years agoHelpfull: Yes(7) No(1)
- 1)5c3*11c8+5c2*11c9+5c1*11c10+5c0*11c11
2)4a=2(2(8+7)), a=15cm
perimeter of semi circle=pi*r,diameter=a=15,so r=7.5
so pi*7.5=23.55cm
3)by combining these points in coordinate axis rhombus is formed.so area of rhombus=1/2(product of diagnoals)
diagnols=distance btwn opposite vertices=square root((x1-x2)^2+(y1-y2)^2)
so area=1/2(4 root(2)*root(13))=2root(26) - 11 years agoHelpfull: Yes(4) No(0)
- 20=(s-f)*x
but given that s/f=3::s=3f
20=(3f-f)*x
x=10/f
now,(2s-1.5f)*x is the new train speed.
solving,((2*3f)-1.5f)*(10/f),we get 45kmph as the new speed - 11 years agoHelpfull: Yes(3) No(0)
- Q3>> formula to find the area of a quadrilateral when co-ords are given is
1/2 * (((x1-x3)*(y2-y4))-((x2-x4)*(y1-y3)))
now use this formula - 11 years agoHelpfull: Yes(2) No(0)
- 5C3x11C8+5C2x11C9+5C1x11C10
where 5c3 is ways of selecting 3 men out of 5
2 men 9 women
1 man 10 woman
- 11 years agoHelpfull: Yes(1) No(1)
- Q2>> let side of square is a therefore,
4a/2=2(8+7) => a=15 (so 15 is diameter of semicircle)
so circumference/perimeter of semi circle = 22/7 * 15 = 47.14 - 11 years agoHelpfull: Yes(1) No(4)
- 1)the selection shouldnot contain more than 3 men.so it can contain 0 men&11 women or 1men and 10 women or 2 men and 9 women or 3 men and 8 women.
11C11+(5C1*11C10)+(5C2*11C9)+(5C3*11C8)
2)let the side of square be x.
perimeter of square is 4x and rectangle is 2(lenght +breadth)
4x=2(8+7)=30.x=7.5.
circumference of semicircle = pi*r=pi*(7.5/2)=11.78
- 11 years agoHelpfull: Yes(1) No(1)
- 1) 5c411c7 + 5c511c6.
2)47.1 cm
3)If the points are (x1, y1), (x2, y2), ..., (x4, y4), then here's the
formula:
2A = (x1y2 - x2y1) + (x2y3 - x3y2) + (x3y4 - x4y3) + (x4y1 - x1y4)
a=1/2((x1y2 - x2y1) + (x2y3 - x3y2) + (x3y4 - x4y3) + (x4y1 - x1y4))
- 11 years agoHelpfull: Yes(0) No(1)
- Ans6:
By using pythagrs Theorem we can find the distance i.e. sqrt(10^2+10^2)=10sqrt2 - 11 years agoHelpfull: Yes(0) No(2)
- BAILORE PRADYUMNA ACHARYA wud u xplain the soln of 4th qn in detail
- 11 years agoHelpfull: Yes(0) No(0)
- 1)2256
5)wrong data
6)10sqrt2 - 11 years agoHelpfull: Yes(0) No(0)
- @Bailore: the answer could be 10sqrt(2)+20
- 11 years agoHelpfull: Yes(0) No(0)
TCS Other Question
6 positive integers are taken at random & multiplied together. what is the probability that the product ends in an odd digit other than 5?
19 people (a1, a2, ..... , a19) are invited to a party. The host and the hostess shake hands with each invitee and also with each other. The invitees shake hands in a circular fashion, i.e. the pairs (a1, a2), (a2, a3), ....,(a18, a19),(a19, a1) shake hands. So, in all there are 58 handshakes. Let S be a set of people such that every pair in S shake hands. The size of S is at most
option
a) 2
b) 3
c) 1
d) 4