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In a 500m race Q starts 15m ahead of P. But P wins the race while Q is still 10m behind. The ratio of their speeds ,(P:Q) assuming that both start at the same time is
a. 20:19
b. 4:5
c. 5:6
d. 4:7
Read Solution (Total 8)
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- when p complete the race q lag of 10 and also it starts 15m ahed so when p comlete
the race q lag of 25m so ration is 500:475 i,e 20:19
- 11 years agoHelpfull: Yes(31) No(0)
- v1:v2 =(d1/t1):(d2/t2)
t1 = t2
so v1:v2 = d1:d2 = 500:(500-10-15) = 500:475 = 20:19
- 11 years agoHelpfull: Yes(8) No(0)
- 20:19 as the ratio will be ratio of the distance covered as the time is same.
- 11 years agoHelpfull: Yes(1) No(0)
- in the same time Qhas covered (500-15-10)mt and P 500mt.
hence as v=d/t;
Vp/Vq=200/475=20/19. - 11 years agoHelpfull: Yes(0) No(0)
- 200:19 is the Ans.
- 11 years agoHelpfull: Yes(0) No(0)
- when p complete the race q lag of 10 and also it starts 15m ahead so when p complete
the race q lag of 25m so ration is 500:475
i,e 20:19
v1:v2 =(d1/t1):(d2/t2)
t1 = t2
so v1:v2 = d1:d2 = 500:(500-10-15) = 500:475 = 20:19
- 10 years agoHelpfull: Yes(0) No(0)
- let time be t sec.
p speed:q speed=500/t:(500-10-15)/t=20:19 - 9 years agoHelpfull: Yes(0) No(0)
- For the same time distance covered by Q=50-15-10=475 while for P=500
Here Speed is proportional to the distance
so, Required ratio=500/475=20/19 - 6 years agoHelpfull: Yes(0) No(0)
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