Two ISB alumni decide to meet at Caf Linger On between 9:30 am and 10:30 am. They agree that the person who arrives first at the cafe would wait for exactly 15 minutes for the other. If each of them arrives at a random time between 9:30 AM and 10:30 AM. What is the probability that the meeting takes place?

a. 7/18
b. 9/16
c. 7/16
d. 11/18

• 9:30-9.45-10-10.15-10.30
  now since A can arrive in any of the four slots and same wid B,so total sample space is 16;
  now suppose A has arrived between 9.30-9.45 then if B arrives in oder 3 slots then
  they dont meet and same with B if a arrives in another 3 slots
  total probability that they dont meet is p(a)*P(b)=3/4*3/4 = 9/16;
  now they meet is 1-9/16=7/16;
• 10 years agoHelpfull: Yes(24) No(2)
• 7/16 is the answer....
  the probability that they meet=1-prob that they don't meet
  prob that they don't meet=(3/4)*(3/4)=9/16
  hence prob that they meet=1-9/16=7/16
• 10 years agoHelpfull: Yes(18) No(3)
• can u explain it clearly....
• 10 years agoHelpfull: Yes(5) No(0)
• hw probability they don't meet is 3/4?
  i think it is reverse of it prob they meet only 3/4.
• 10 years agoHelpfull: Yes(3) No(1)
• both friends may meet at 9.30 or 9.45 or 10.00 or 10.15 or inbetween the two timings. so (4+3)/16=7/16.
• 10 years agoHelpfull: Yes(2) No(0)
• ANS:7/16
  There are four 15 min in one hour.
  now we first calculate the probablity that they dont meet
  which is
  for person A=45/60=3/4
  for person B=45/60=3/4
  now 3/4*3/4=9/16
  
  hence the total probablity is
  1-(9/16)=7/16
• 8 years agoHelpfull: Yes(2) No(0)
• @bailore:..plss explain it clearly
• 10 years agoHelpfull: Yes(0) No(0)
• Very Nice Question !!!
• 10 years agoHelpfull: Yes(0) No(0)
• why 3/4 is two times multiplied?
• 9 years agoHelpfull: Yes(0) No(0)