TCS
Company
Logical Reasoning
Number Series
find the value of 1!+2!+.....+50!
Read Solution (Total 10)
-
- 50!+49!+48!+.....1!
50![1+(1/50)+(1/49*50)+....]
50!(1+0.2+0.004+....)[neglect lower values]
50!*1.02 is the answer
- 11 years agoHelpfull: Yes(19) No(1)
- 51!-1
- 11 years agoHelpfull: Yes(6) No(8)
- it would be 51!/5o
- 11 years agoHelpfull: Yes(5) No(6)
- 3.1035*10^64.....but i don't know the exact solution..
- 11 years agoHelpfull: Yes(4) No(4)
- we have common 50! fro the series.......
50![1!+49!/50!]=51!/50 - 11 years agoHelpfull: Yes(4) No(0)
- we can write it as..
50!+49!+48!+.........+1!
50![1+(1/50)+(1/50*49)+............+(1/50!)]
50![1+0.2] (neglecting higher order terms)
50!*1.02
3.102237507*10^64
which is equal to 51!/50......ans
ans=51!/50 - 11 years agoHelpfull: Yes(1) No(2)
- formula:1!+2!+......n!=(n+1)!/n
so answer is 51!/50 - 11 years agoHelpfull: Yes(1) No(1)
- 50!-1
- 11 years agoHelpfull: Yes(0) No(4)
- formula for n! is=n(n-1)!
so answer is=50(49!) - 11 years agoHelpfull: Yes(0) No(4)
- 50!-1 Ans.
- 11 years agoHelpfull: Yes(0) No(0)
TCS Other Question