log2 = 0.3010 and log3 = 0.4771 then the value of log(9/2) = ?
A.0.25 B. None C.0.75 D. 0.65

• log 9/2 = log 9 - log2= 2log3-log2=2*.4771-.3010=.9542-.3010=.6532
  
  So ans is D =.65
• 10 years agoHelpfull: Yes(7) No(1)
• D. 0.653
  2log3-log2=2*0.477-0.301=0.653
• 10 years agoHelpfull: Yes(1) No(1)
• we have to know two basic formulae to solve
  log x^n= nlogx and log x/y= logx-logy
  now its very easy
  log(9/2)=log9-log2
  =2log3-log2=.65
• 10 years agoHelpfull: Yes(1) No(1)
• D.0.65
  log(9/2)=log9-log2
  log3*log3-log2
  log(a)*log(b)=log(a+b)
  log(3+3)-log(2)
  0.4771+0.4771-0.3010=0.65
• 6 years agoHelpfull: Yes(0) No(0)