George works 5 times faster than his son and hence completes a job 40 days earlier than his son Find

let George does a job in 'x' days
his son does that job in '5x' days
so, 5x-x =40
=> x=10
work of george in 1 day= 1/10
work of his son in 1 day= 1/50
total work in 1 day= 1/10+1/50=6/50
6/50 work =1 day
1 work= 50/6 days
ANS- 50/6 days
11 years agoHelpfull: Yes(14) No(0)
son=x
george=5x
so,5x=x+40
x=10
therefore,1/10+1/50=6/50
ans=50/6=25/3
11 years agoHelpfull: Yes(6) No(0)
according to the ques...
son(x)=george(x/5)+40 days..
it gives x=50days
therefore geogre completes work in 10 days and his son in 50days
hence they both can do 10%+2%=12%work ina day..
therefore days = 100/12=8.33 or 9 days
11 years agoHelpfull: Yes(5) No(6)
days taken by
George=x, son=5x (inversely proportion to work). so diiference is 5x-x=40 thus x=10. i.e. george takes 10 days and son=50 days. by shortcut, days taken by working together = lcm of(10,50) =50
50/6(total parts of work done by each in 1 day)=8.33 days.
11 years agoHelpfull: Yes(1) No(0)
a=6b,a-b=40
so b=48days&a=8days
so together 48/7 days
11 years agoHelpfull: Yes(0) No(14)

George works 5 times faster than his son and hence completes a job 40 days earlier than his son. Find the time they would take to finish the job working together.