The radii of top and bottom of a bucket are 25cms and 20cms respectively. If the volume of the bucket is 67100 cubic cms, find the height of the bucket.

• V=(PI/3)*H*[(R1)^2+(R1*R2)+(R2)^2]
  
  THUS H=42
• 11 years agoHelpfull: Yes(16) No(7)
• volume = pie*h*(d^2+b^2+d*b)/12
  where d and b are the diameters of the two faces of the bucket
  => 67100*12/pie=h*(50^2+40^2+50*40)
  =42 cm Answer
  
• 11 years agoHelpfull: Yes(7) No(4)
• Volume of the Frustrum is cone= 3.14*h(R^2 + r^2+ Rr)/3
  Putting the values
  V=67100 R=25 r=20
  Height of the frustrum is 462cms
• 11 years agoHelpfull: Yes(3) No(1)
• 284.67 because of Volume=1/3pi*r^2*(R^2-r^2)*h
• 11 years agoHelpfull: Yes(0) No(4)
• height is 42.17 cm.
• 11 years agoHelpfull: Yes(0) No(0)
• π(h/3)(R^2 + r^2 +R*r)=67100
  
  h=(67100*3)/(1525π)=42.03
• 6 years agoHelpfull: Yes(0) No(0)