b,c,d are positive integers and are in GP and n,o,p are in AP.what is the value of
(p-o)logb+(n-p)logc +(b-n)logd

• (p-o)logb+(n-p)logc +(b-n)logd -(1)
  b,c,d are in G.P,So that b/c = c/d ,and then n,o,p are in A.P so that 2o=p+n.-(2)
  From equation (1)
  plogb-ologb+nlogc-plogc+blogd-nlogd,it can be written as plog(b/c)+nlog(c/d)+blogd-ologb
  from equation(2) b/c =c/d,so that (p+n)log(b/c)-ologb+blogd-(3)
  p+n=2o,2olog(b/c)-ologb+blogd=>olog(b^2/c^2)-ologb+blogd
  olog(b/c^2)+blogd,c^2=bd,olog(1/d)+blogd=>(b-o)logd
  (p-o)logb+(n-p)logc +(b-n)logd=(b-o)logd
• 11 years agoHelpfull: Yes(1) No(0)