when numbers are written in base b,we have 12*25=333.the value of b is?

• Let the base be A..
  Now
  12 can be written as (A+2) in base A system;
  25 can be Written as (2A+5) in base A System
  333 can be Written as ( 3A^2+3A+3)
  Now put the value and solve the quadratic equation..(A^2-6A-7=0)
  Ans. 7
• 11 years agoHelpfull: Yes(26) No(5)
• ans : 7 as
  (b+2)*(2b+5)=3b^2+3b+3
  solve to get b=7 or -1;
  so b=7
• 11 years agoHelpfull: Yes(8) No(1)
• can u expalin it elaborately @sunandini...
• 11 years agoHelpfull: Yes(0) No(0)
• (1*b^1+2)(2*b^0+5) = (3*b^2+3*b+3)
  
  Now putting the values from options....,
  Since option is not given here after solving we get 7.
• 11 years agoHelpfull: Yes(0) No(0)