In this series
1212212221222212222212222221.....
find the sum of first 1234 trems

• we may write it as 1+(20+1)+(200+20+1)+(2000+200+20+1).......
  now., (1+1+1+..1234 times +20+200+2000..each 1233 times)
  so, 1234+ 1233*2(10+100+1000+....form a Gp)
  
  so acco to me ansr should,,1234+2466*10((10^1233-1)/10-1)
  i used sum of Gp formula.
  i don't knw its right or wrong,guys plz giv ur suggestions
• 10 years agoHelpfull: Yes(1) No(2)
• n(n+1)/2=10
  
• 10 years agoHelpfull: Yes(0) No(2)