A point p inside the triangle ABC and distances from point p from A,B,C, is 6,8,11.Find the perimeter of the triangle

• ans is 46..drop a perpendicular at one part
  
  it divides side into a,b
  
  now 121-a^2=64-b^2
  
  57=(a+b)(a-b)
  
  so a+b=19
  
  similarly for other parts we get sides as 14,13
  
  so ans 46
  
  
• 11 years agoHelpfull: Yes(13) No(6)
• i suggest just use Pythagoras theorem to solve it
• 11 years agoHelpfull: Yes(0) No(12)