(222224*444445*222221+666668)/(222222)^2

• let x=222222,
  then we can form as (x+2)*(2x+1)*(x-1)+(3x+2)/x^2,
  simply above form we get 2x+3=> 2(222222)+3 = 444447
  
• 11 years agoHelpfull: Yes(75) No(1)
• ans: 2(222222)+3=444447
  take 222222 as x;
  then.. we get the polynomial: {[(x+2)(2x+4)(x-1)]+(3x+2)}/x^2;
  expanding we get: (2x^3+3x^2)/x^2;
  ans 2x+3=444447
• 11 years agoHelpfull: Yes(10) No(5)
• ANS:444447
  let x=222222,
  then we can form as (x+2)*(2x+1)*(x-1)+(3x+2)/x^2,
  simply above form we get 2x+3=> 2(222222)+3 = 444447
• 11 years agoHelpfull: Yes(4) No(0)
• let 222222=a
  .
  {(a+2)*(2a+1)*(a-1)+(3a+2)}/a^2
  .
  while solving we can get final step as
  =2a+3
  hence a=222222
  then
  =2*222222+3
  =444447
• 11 years agoHelpfull: Yes(1) No(0)
• consider x= 2222222...and solve the problem..u will got answer 4444447
• 11 years agoHelpfull: Yes(1) No(0)
• Simple multiply and devide them by 222222*222222
  ans=444447
• 11 years agoHelpfull: Yes(0) No(6)
• (x+2)*(2x+1)*(x-1)+(3x+2)/x^2
  
  The answer will be 4444447.
• 11 years agoHelpfull: Yes(0) No(0)