TCS
Company
Numerical Ability
Area and Volume
A boy is cycling such that the wheel of his cycle is undergoing 420 revolutions per minute. The diameter of the wheel is 50cm. Find his speed in kmph.
Read Solution (Total 13)
-
- Ans is 39.6 Kmph
distance covered in 1 revolution=.25*2*(22/7)=1.57142
so, distance covered in 7 revolution or in 1 second=1.57142*7=11 (Because there are 7 revolution in 1 second)
hence speed= 11 m/s or 11*(18/5)= 39.6 kmph - 11 years agoHelpfull: Yes(39) No(1)
- 1 min= 420 revolutions
diameter of wheel = 50, so radius will be 25
or 0.25 m.
distance covered in 1min= 420*2*pie*25
=660
nw in 60 s = 660
1 s = 11m/s - 11 years agoHelpfull: Yes(9) No(1)
- total distance covered in 1 minute= 2*pie*r*420
soving it gives 11m/sec - 11 years agoHelpfull: Yes(5) No(2)
- 39.6 kmph is the ans
- 11 years agoHelpfull: Yes(4) No(0)
- ans is - 22 m/sec
- 11 years agoHelpfull: Yes(2) No(4)
- howz this.....plse explain it
- 11 years agoHelpfull: Yes(0) No(0)
- its 39.564
revolutions per second is 420/60=7
total distance traveled is 7*2*pi*d/200 m
so in kmph multiply the above value by 18/5
- 11 years agoHelpfull: Yes(0) No(0)
- (420*50*60)/100000= 12.6kmph
- 11 years agoHelpfull: Yes(0) No(0)
- total distance covered in 1 minute= 2*(22/7)*r*420*(1/60)sec
soving it gives 11m/sec now covert it into km/h=11*(18/5) - 11 years agoHelpfull: Yes(0) No(0)
- 39.6 km/hr
- 11 years agoHelpfull: Yes(0) No(0)
- 39.6 should be the ans
- 11 years agoHelpfull: Yes(0) No(0)
- since, in 1 min the revolution= 420
distance covered in 1 min= 2*pi*r*n i.e 2*22/7*25/100*420
then speed in m/s= (2*22/7*25/100*420)/60= 11 m/s
in Kmph= 11*18/5=39.8 Kmph - 11 years agoHelpfull: Yes(0) No(0)
- 11 m/s answer !!!!
- 11 years agoHelpfull: Yes(0) No(0)
TCS Other Question