1 1 2 2 3 3 2013 2013

2014!-1 because sum of two terms is equal to 5 we can write this 3!-1 and sum upto 3 terms is equal to 4!-1
hence we can write sum upto 2013 terms is 2014!-1
11 years agoHelpfull: Yes(36) No(0)

Ans is 2014!-1
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1(1!) = 1 --> 2!-1
1(1!)+2(2!) = 5 --> 3!-1
1(1!)+2(2!)+3(3!) = 23 --> 4!-1
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1(1!)+2(2!)+3(3!+..+2012(2012!)+2013(2013!) = 2014!-1
11 years agoHelpfull: Yes(21) No(0)
Ans is 2014!-1
for any such type of series sum is always (n+1)!-1
11 years agoHelpfull: Yes(12) No(0)
(2-1)1!+(3-1)2!+(4-1)3!+.........(2014-1)2013!
2!-1!+3!-2!+4!-3!.........2014!-2013
2014!-1
11 years agoHelpfull: Yes(3) No(0)
2014!-1
No solution, learn it
11 years agoHelpfull: Yes(3) No(1)
b/c we know 1.1! + 2.2! + 3.3! + .... + n.n! =(n+1)! - 1
so here n=2013
now (2013+1)! - 1 =2014! - 1 ans
11 years agoHelpfull: Yes(2) No(0)
1(1!)=1 ⇒ 2!-1
1(1!)+2(2!)=1+4=5 ⇒ 3!-1
1(1!)+2(2!)+3(3!)=1+4+18=23 ⇒ 4!-1
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1(1!)+2(2!)+3(3!)+........+2012(2012!)=2013!-1
11 years agoHelpfull: Yes(1) No(2)
simply follow this formula-> n(n!)=(n+1)!-n!
take right side and then-> (1+1)!-1!
(2+1)!-2!
. .
at last (2013+1)!-2013!
only 2014!-1! left
11 years agoHelpfull: Yes(1) No(1)
sum of 1.1!+2.2! is 5 which is equal to 6-1 or 3!-1
sum of 1.1!+2.2!+3.3! is 23 which is equal to 24-1 or 4!-1
similarly othrs can be calculated
ans will be 2014!-1
11 years agoHelpfull: Yes(0) No(0)
!2014-1 will be the answer !!!
11 years agoHelpfull: Yes(0) No(0)

1!1+2!2+3!3+....+2013!2013.