Three runners A,B and C run a race,with runner A finishing 24 meters ahead of B and 36meters ahead of C,while runner B finishes 16 meters ahead of run C.Each runner travels the entire distance at a constant distance.what was the length of race ?

a)72m
b)96m
c)120m
d)144m

• let race is of= x meters
  when A completed the race, distance covered by B= (x-24)and by C= (x-36)
  when B completed the race (B=x), distance covered by C= (x-16)
  => (x-24)/x = (x-36)/(x-16)
  => x = 96m
• 11 years agoHelpfull: Yes(72) No(6)
• @ Disha Agarwal: How did you get the equation(x-24)/x=(x-36)/(x-16). Please explain this i cant follow.
• 11 years agoHelpfull: Yes(14) No(2)
• let a,b,c are speeds of A,B,C respectevely and x is total distance
  so,
  a/b=x/x-24----1
  a/c=x/x-36----2
  b/c=x-24/x-36--3
  b/c=x/x-16-----4
  from 3 and 4
  x=96
• 11 years agoHelpfull: Yes(13) No(0)
• b)96
  
  Let race distance=x
  (x/A)=(x-24/B)=(x-36/C)-------1
  (x/B)=(x-16/C)-------2
  solve 1 and 2.
• 11 years agoHelpfull: Yes(12) No(3)
• let total distance be d.
  let speed of A,B,C be x,y,z respectively
  d/x= (d-24)/y= (d-36)/z
  24/y+16/z= 36/z i.e 24/y= 20/z i.e
  y= 6/5*z
  (d-24)/y= (d-36)/z i.e (d-24)*5/6z= (d-36)/z after solving this equation d= 96 m
• 11 years agoHelpfull: Yes(6) No(3)
• ans is a)72 because
  total distance between a and c is 36
  distance of b to c is 36-24=12 in 1st point,while we considering 2nd point
  b to c is 16
  so 16-12=4
  hence total distance is 36+24+12=72
  
• 11 years agoHelpfull: Yes(5) No(22)
• what is meant by ... travels the entire distance at A CONSTANT DISTANCE ?
  please explain i m not able to get the question.
• 11 years agoHelpfull: Yes(2) No(0)
• let race is of= x meters
  when A completed the race, distance covered by B= (x-24)and by C= (x-36)
  when B completed the race (B=x), distance covered by C= (x-16)
  => (x-24)/x = (x-36)/(x-16)
  => x = 96m
• 10 years agoHelpfull: Yes(2) No(0)
• On what basis you wrote this equation so casually. @diksha
• 9 years agoHelpfull: Yes(1) No(1)