how many three digit numbers when divided by
5,6 and 7 leave a remainder of 2,3 and 5 respectively?

• 1st series- 102,107,112,117,122........
  2nd series- 105,111,117,123,129........
  3rd series- 103,110,117,124,131........
  
  therefore the our first no. is - 117
  
  and the LCM of 5,6,7 is 210.
  
  so keep on adding 210 in 117
  final series is - 117,327,537,747,957
  
  so the total no.s are- 5 (Ans)
• 11 years agoHelpfull: Yes(40) No(0)
• 5.
  117,327,537,747,957
• 11 years agoHelpfull: Yes(20) No(4)
• the three digit num is between 100 to 999
  l.c.m of (5-2),(6-3) and (7-5) i.e 3,3,2= 6
  now the num which is divisible by 6 is included....
  the 1st 3-digit num is 108 and last 996.
  so 996= 108+(n-1)*6 i.e n= 149
• 11 years agoHelpfull: Yes(19) No(27)
• Ans is 4
  167,377,587,797
• 11 years agoHelpfull: Yes(4) No(13)
• ans=117
  117/5=remainder=2
  117/6=rem=3
  117/7=rem=5
  
• 11 years agoHelpfull: Yes(2) No(13)
• ans is 167
• 11 years agoHelpfull: Yes(1) No(13)
• ans is 459
  
• 11 years agoHelpfull: Yes(1) No(9)
• 117,327,537,747,957 Ans.
• 11 years agoHelpfull: Yes(0) No(0)