The difference between two no is 9 and the product of the two is 14.What is the square of their sum?

• they ask for square of their sum i.e.,
  (a+b)^2=(a-b)^2+4ab
  =(9*9)+4*14
  =137
  
• 12 years agoHelpfull: Yes(64) No(10)
• Use the formula,(x-y)^2 = x^2 + y^2 - 2xy ,x^2 + y^2 = 81+28 = 109
• 12 years agoHelpfull: Yes(9) No(55)
• given:-
  a-b=9 and ab=14
  => (a-b)^2 + 4ab = (a+b)^2
  => (9*9) + (4*14) =(a+b)^2
  => (a+b)^2 = 137
• 8 years agoHelpfull: Yes(4) No(0)
• given,
  10x-y=9 ...... eq(1)
  10x*y=14.....eq(2)
  now squaring both side eq (1) gives.....
  10x^2 + y^2 - 2*10x*y=9*9
  10x^2 +y^2 = 81+2*14 =109
  
• 9 years agoHelpfull: Yes(0) No(4)
• given: x-y = 9
  xy = 14
  (x-y)^2 = x^2 + y^2 - 2xy
  81 = x^2 + y^2 -2*14
  109 = x^2 + y^2
• 8 years agoHelpfull: Yes(0) No(4)
• we know that
  (x+y)^2=(x-y)^2+4xy.....equation (i)(basic formulae)
  now putting the values of x-y and xy in equation (i)...we had
  (x+y)^2=(9)^2+4*14
  =81+56
  =137(which is the required answer)
  
  
  
  
  
  
  
• 7 years agoHelpfull: Yes(0) No(0)
• 109
  (x-y)^2=x^2+j^2-2xy
• 5 years agoHelpfull: Yes(0) No(0)
• Solution formula (a-b)^2+4ab
• 1 year agoHelpfull: Yes(0) No(0)